zotmeister: a <i>Sudoku</i> puzzle (quadrum)
zotmeister ([personal profile] zotmeister) wrote2005-07-24 11:39 am
Entry tags:

Puzzlesmith 1 Results


I am pleased to report that I had only one fewer entry than I expected to receive. Both were perfectly valid, with a unique solution and rotationally symmetric givens. It turns out that with my own "entry" included, all three of us each used only eight givens. I'd imagine six would be impossible, but I certainly haven't proven this. All three puzzles are duplicated below - enjoy (see Puzzle 7 for instructions):



I thought it interesting to note the variances in our compositions. Cameron pulled off what I was aiming for at first and failed to do with only eight givens: no givens on the outer border; Jezendar has a parity apartheid thing going, with the even-celled polyominoes separated from the odd-celled (which e claims e didn't notice until after e built it); my givens are all different values.

With the assistance of random.org, Jezendar has been selected to receive the fifty-dollar prize. Congratulations! You should be getting an email from PayPal shortly.

Shameless plug: there's another way to get a hundred dollars out of me open right now. If that isn't your proverbial cup of tea, fear not - I'm already planning more puzzle contests. - ZM

[identity profile] jezendar.livejournal.com 2005-07-24 09:35 pm (UTC)(link)
I can't help but notice that, between the parentheses, you used the gender-neutral 'e' twice and the gender-not-neutral 'he' once. Just to let you know, you don't have to worry about hiding information about me; I have recently placed my real name in my info page.

As for the contest results, you say you received one less entry than expected and make no mention of any entries except Cameron's and my own. Does this mean you were expecting three entries? If so, then I'm glad that you did not receive TWO less than expected; wouldn't have been much of a contest...

By the way, is it ok to post a comment mentioning the number of polyominoes in the puzzle. I know such a post would not normally be acceptable because it would give away part of the puzzle answer, but in this case the number of polyominoes in the puzzle would already be known to anyone who read the contest rules.

[identity profile] jezendar.livejournal.com 2005-07-26 09:00 pm (UTC)(link)
The comment I wanted to make is a second note on the variances between our three puzzles, specifically concerning the number of unmarked polyominoes. As you have already mentioned, your puzzle uses eight different givens. This also means that all eight polyominoes are labeled. In his puzzle, Cameron labeled seven polyominoes, leaving the monomino unlabeled. My puzzle continues this pattern, leaving both the monomino and the domino unlabeled. In addition, two of the givens in my puzzle (specifically the '4' and the '5') can switch positions without invalidating the puzzle.
I considered doing this when I noticed the 'parity apartheid', as you put it. But, I decided that the current setup was more interesting.

As for solving my puzzle, a hint I would give to people who have not read the contest rules is:
Add together the values of the eight givens and compare that total to the number of available squares in the puzzle.

[identity profile] barryr.livejournal.com 2005-07-24 10:47 pm (UTC)(link)
I was hoping to give it a try at least- but with the choice between "do my damn WebCT schoolwork" and "try a logic puzzle that won't gain me the three credits that the course shall", a certain amount of logic prevailed in a different way. Sadly not a way that wins me anything, but I could always say I won three college credits in a lottery.

Who else thinks that college credits should be awarded kinda like tickets from a game machine at Dave & Buster's? Meeeeeeeee.

[identity profile] dumbgenius.livejournal.com 2006-01-12 04:53 am (UTC)(link)
I had a go at this, and couldn't beat 8 givens.

Though it doesn't follow the rules of the competition, I particularly enjoyed the design of the following puzzle -
8....4
......
.67...
...68.
......
B....7
where B = 11